Base | Representation |
---|---|
bin | 100011011111001000001011… |
… | …1010011111011011011011111 |
3 | 1111221012102121020121202220101 |
4 | 1012332100113103323123133 |
5 | 311403111124140213343 |
6 | 3023511443442201531 |
7 | 122514321504320626 |
oct | 10676202723733337 |
9 | 1457172536552811 |
10 | 312141434304223 |
11 | 90504491177457 |
12 | 2b0131269532a7 |
13 | 10522a708862c4 |
14 | 5711a243246bd |
15 | 26147ad36ee4d |
hex | 11be4174fb6df |
312141434304223 has 2 divisors, whose sum is σ = 312141434304224. Its totient is φ = 312141434304222.
The previous prime is 312141434304209. The next prime is 312141434304229. The reversal of 312141434304223 is 322403434141213.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312141434304223 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312141434304229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156070717152111 + 156070717152112.
It is an arithmetic number, because the mean of its divisors is an integer number (156070717152112).
Almost surely, 2312141434304223 is an apocalyptic number.
312141434304223 is a deficient number, since it is larger than the sum of its proper divisors (1).
312141434304223 is an equidigital number, since it uses as much as digits as its factorization.
312141434304223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 37.
Adding to 312141434304223 its reverse (322403434141213), we get a palindrome (634544868445436).
The spelling of 312141434304223 in words is "three hundred twelve trillion, one hundred forty-one billion, four hundred thirty-four million, three hundred four thousand, two hundred twenty-three".
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