Base | Representation |
---|---|
bin | 100011011111001000111010… |
… | …1011010100110010011101111 |
3 | 1111221012120200021102110200022 |
4 | 1012332101311122212103233 |
5 | 311403122342324023043 |
6 | 3023512304241352355 |
7 | 122514405565052123 |
oct | 10676216532462357 |
9 | 1457176607373608 |
10 | 312143013111023 |
11 | 90505121393366 |
12 | 2b0134a76386bb |
13 | 10522c629ab803 |
14 | 5711b33c9d583 |
15 | 2614851c84868 |
hex | 11be4756a64ef |
312143013111023 has 2 divisors, whose sum is σ = 312143013111024. Its totient is φ = 312143013111022.
The previous prime is 312143013111001. The next prime is 312143013111029. The reversal of 312143013111023 is 320111310341213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312143013111023 - 230 = 312141939369199 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 312143013110983 and 312143013111001.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312143013111029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156071506555511 + 156071506555512.
It is an arithmetic number, because the mean of its divisors is an integer number (156071506555512).
Almost surely, 2312143013111023 is an apocalyptic number.
312143013111023 is a deficient number, since it is larger than the sum of its proper divisors (1).
312143013111023 is an equidigital number, since it uses as much as digits as its factorization.
312143013111023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 312143013111023 its reverse (320111310341213), we get a palindrome (632254323452236).
The spelling of 312143013111023 in words is "three hundred twelve trillion, one hundred forty-three billion, thirteen million, one hundred eleven thousand, twenty-three".
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