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312143014330933 is a prime number
BaseRepresentation
bin100011011111001000111010…
…1011111010000001000110101
31111221012120200100201110002011
41012332101311133100020311
5311403122343132042213
63023512304323444221
7122514405611322532
oct10676216537201065
91457176610643064
10312143014330933
1190505122046955
122b0134a7b26671
1310522c63017b56
145711b340d9d89
152614851e2603d
hex11be4757d0235

312143014330933 has 2 divisors, whose sum is σ = 312143014330934. Its totient is φ = 312143014330932.

The previous prime is 312143014330891. The next prime is 312143014330967. The reversal of 312143014330933 is 339033410341213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 250768982761969 + 61374031568964 = 15835687^2 + 7834158^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-312143014330933 is a prime.

It is a super-2 number, since 2×3121430143309332 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312143014334933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156071507165466 + 156071507165467.

It is an arithmetic number, because the mean of its divisors is an integer number (156071507165467).

Almost surely, 2312143014330933 is an apocalyptic number.

It is an amenable number.

312143014330933 is a deficient number, since it is larger than the sum of its proper divisors (1).

312143014330933 is an equidigital number, since it uses as much as digits as its factorization.

312143014330933 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 209952, while the sum is 40.

The spelling of 312143014330933 in words is "three hundred twelve trillion, one hundred forty-three billion, fourteen million, three hundred thirty thousand, nine hundred thirty-three".