Base | Representation |
---|---|
bin | 11101000100100001… |
… | …001110110010111001 |
3 | 2222120101021102020121 |
4 | 131010201032302321 |
5 | 1002411332124423 |
6 | 22201211253241 |
7 | 2153343311425 |
oct | 350441166271 |
9 | 88511242217 |
10 | 31214333113 |
11 | 1226874a517 |
12 | 607174a221 |
13 | 2c35b374c2 |
14 | 1721829b85 |
15 | c2a54645d |
hex | 74484ecb9 |
31214333113 has 2 divisors, whose sum is σ = 31214333114. Its totient is φ = 31214333112.
The previous prime is 31214333069. The next prime is 31214333147. The reversal of 31214333113 is 31133341213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 22451126569 + 8763206544 = 149837^2 + 93612^2 .
It is a cyclic number.
It is not a de Polignac number, because 31214333113 - 233 = 22624398521 is a prime.
It is not a weakly prime, because it can be changed into another prime (31214333173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15607166556 + 15607166557.
It is an arithmetic number, because the mean of its divisors is an integer number (15607166557).
Almost surely, 231214333113 is an apocalyptic number.
It is an amenable number.
31214333113 is a deficient number, since it is larger than the sum of its proper divisors (1).
31214333113 is an equidigital number, since it uses as much as digits as its factorization.
31214333113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1944, while the sum is 25.
Adding to 31214333113 its reverse (31133341213), we get a palindrome (62347674326).
The spelling of 31214333113 in words is "thirty-one billion, two hundred fourteen million, three hundred thirty-three thousand, one hundred thirteen".
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