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312210121012513 is a prime number
BaseRepresentation
bin100011011111101000001010…
…1010110111011010100100001
31111221102222220010210002020021
41012333100111112323110201
5311410222311434400023
63024003203300513441
7122522302563600523
oct10677202526732441
91457388803702207
10312210121012513
1190530629012a79
122b0244b59ab881
1310529398bc0a69
14571509c759a13
15261647d51735d
hex11bf4155bb521

312210121012513 has 2 divisors, whose sum is σ = 312210121012514. Its totient is φ = 312210121012512.

The previous prime is 312210121012501. The next prime is 312210121012631. The reversal of 312210121012513 is 315210121012213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 306927694499904 + 5282426512609 = 17519352^2 + 2298353^2 .

It is a cyclic number.

It is not a de Polignac number, because 312210121012513 - 25 = 312210121012481 is a prime.

It is a super-2 number, since 2×3122101210125132 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (312210121612513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156105060506256 + 156105060506257.

It is an arithmetic number, because the mean of its divisors is an integer number (156105060506257).

Almost surely, 2312210121012513 is an apocalyptic number.

It is an amenable number.

312210121012513 is a deficient number, since it is larger than the sum of its proper divisors (1).

312210121012513 is an equidigital number, since it uses as much as digits as its factorization.

312210121012513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 312210121012513 its reverse (315210121012213), we get a palindrome (627420242024726).

The spelling of 312210121012513 in words is "three hundred twelve trillion, two hundred ten billion, one hundred twenty-one million, twelve thousand, five hundred thirteen".