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312212021044241 is a prime number
BaseRepresentation
bin100011011111101001000011…
…0100110111110010000010001
31111221110011210120000200202202
41012333102012212332100101
5311410240204341403431
63024004120013052545
7122522400634601603
oct10677220646762021
91457404716020682
10312212021044241
119053141358aa2a
122b024946187155
131052960c735ba6
1457151dcc31173
15261654022e8cb
hex11bf4869be411

312212021044241 has 2 divisors, whose sum is σ = 312212021044242. Its totient is φ = 312212021044240.

The previous prime is 312212021044207. The next prime is 312212021044243. The reversal of 312212021044241 is 142440120212213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 312140556250000 + 71464794241 = 17667500^2 + 267329^2 .

It is a cyclic number.

It is not a de Polignac number, because 312212021044241 - 214 = 312212021027857 is a prime.

Together with 312212021044243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (312212021044243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156106010522120 + 156106010522121.

It is an arithmetic number, because the mean of its divisors is an integer number (156106010522121).

Almost surely, 2312212021044241 is an apocalyptic number.

It is an amenable number.

312212021044241 is a deficient number, since it is larger than the sum of its proper divisors (1).

312212021044241 is an equidigital number, since it uses as much as digits as its factorization.

312212021044241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 312212021044241 its reverse (142440120212213), we get a palindrome (454652141256454).

The spelling of 312212021044241 in words is "three hundred twelve trillion, two hundred twelve billion, twenty-one million, forty-four thousand, two hundred forty-one".