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31221312012043 is a prime number
BaseRepresentation
bin1110001100101010001110…
…01101100011111100001011
311002112201122220201020212221
413012111013031203330023
513043012221333341133
6150222512302114511
76401444134246156
oct706250715437413
9132481586636787
1031221312012043
119a4797a76923a
123602a9627ba37
13145620718416a
1479d196126c9d
153922109e4a2d
hex1c6547363f0b

31221312012043 has 2 divisors, whose sum is σ = 31221312012044. Its totient is φ = 31221312012042.

The previous prime is 31221312012031. The next prime is 31221312012083. The reversal of 31221312012043 is 34021021312213.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31221312012043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31221312011999 and 31221312012017.

It is not a weakly prime, because it can be changed into another prime (31221312012013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15610656006021 + 15610656006022.

It is an arithmetic number, because the mean of its divisors is an integer number (15610656006022).

Almost surely, 231221312012043 is an apocalyptic number.

31221312012043 is a deficient number, since it is larger than the sum of its proper divisors (1).

31221312012043 is an equidigital number, since it uses as much as digits as its factorization.

31221312012043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 31221312012043 its reverse (34021021312213), we get a palindrome (65242333324256).

The spelling of 31221312012043 in words is "thirty-one trillion, two hundred twenty-one billion, three hundred twelve million, twelve thousand, forty-three".