Base | Representation |
---|---|
bin | 1001000101100011111… |
… | …01110111100111011011 |
3 | 1002211220101110122222122 |
4 | 10202301331313213123 |
5 | 20103413144244011 |
6 | 355233343411455 |
7 | 31362121242653 |
oct | 4426175674733 |
9 | 1084811418878 |
10 | 312223431131 |
11 | 11045aa94aa7 |
12 | 50616bb3b8b |
13 | 2359a3627b1 |
14 | 1117c6c1363 |
15 | 81c58663db |
hex | 48b1f779db |
312223431131 has 2 divisors, whose sum is σ = 312223431132. Its totient is φ = 312223431130.
The previous prime is 312223431103. The next prime is 312223431151. The reversal of 312223431131 is 131134322213.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312223431131 - 222 = 312219236827 is a prime.
It is a super-3 number, since 3×3122234311313 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 312223431131.
It is not a weakly prime, because it can be changed into another prime (312223431151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156111715565 + 156111715566.
It is an arithmetic number, because the mean of its divisors is an integer number (156111715566).
Almost surely, 2312223431131 is an apocalyptic number.
312223431131 is a deficient number, since it is larger than the sum of its proper divisors (1).
312223431131 is an equidigital number, since it uses as much as digits as its factorization.
312223431131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592, while the sum is 26.
Adding to 312223431131 its reverse (131134322213), we get a palindrome (443357753344).
The spelling of 312223431131 in words is "three hundred twelve billion, two hundred twenty-three million, four hundred thirty-one thousand, one hundred thirty-one".
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