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31223200133113 is a prime number
BaseRepresentation
bin1110001100101101101111…
…10000001010111111111001
311002112220112111112202001221
413012112313300022333321
513043030103213224423
6150223423511112041
76401542002102262
oct706266760127771
9132486474482057
1031223200133113
119a4875954057a
123603322672621
1314564483b8b71
1479d2d4bbb969
153922c1657e5d
hex1c65b7c0aff9

31223200133113 has 2 divisors, whose sum is σ = 31223200133114. Its totient is φ = 31223200133112.

The previous prime is 31223200132997. The next prime is 31223200133129. The reversal of 31223200133113 is 31133100232213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27294229974544 + 3928970158569 = 5224388^2 + 1982163^2 .

It is a cyclic number.

It is not a de Polignac number, because 31223200133113 - 217 = 31223200002041 is a prime.

It is not a weakly prime, because it can be changed into another prime (31223200131113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15611600066556 + 15611600066557.

It is an arithmetic number, because the mean of its divisors is an integer number (15611600066557).

Almost surely, 231223200133113 is an apocalyptic number.

It is an amenable number.

31223200133113 is a deficient number, since it is larger than the sum of its proper divisors (1).

31223200133113 is an equidigital number, since it uses as much as digits as its factorization.

31223200133113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 31223200133113 its reverse (31133100232213), we get a palindrome (62356300365326).

The spelling of 31223200133113 in words is "thirty-one trillion, two hundred twenty-three billion, two hundred million, one hundred thirty-three thousand, one hundred thirteen".