Base | Representation |
---|---|
bin | 1110001100101101101111… |
… | …10000001010111111111001 |
3 | 11002112220112111112202001221 |
4 | 13012112313300022333321 |
5 | 13043030103213224423 |
6 | 150223423511112041 |
7 | 6401542002102262 |
oct | 706266760127771 |
9 | 132486474482057 |
10 | 31223200133113 |
11 | 9a4875954057a |
12 | 3603322672621 |
13 | 14564483b8b71 |
14 | 79d2d4bbb969 |
15 | 3922c1657e5d |
hex | 1c65b7c0aff9 |
31223200133113 has 2 divisors, whose sum is σ = 31223200133114. Its totient is φ = 31223200133112.
The previous prime is 31223200132997. The next prime is 31223200133129. The reversal of 31223200133113 is 31133100232213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27294229974544 + 3928970158569 = 5224388^2 + 1982163^2 .
It is a cyclic number.
It is not a de Polignac number, because 31223200133113 - 217 = 31223200002041 is a prime.
It is not a weakly prime, because it can be changed into another prime (31223200131113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15611600066556 + 15611600066557.
It is an arithmetic number, because the mean of its divisors is an integer number (15611600066557).
Almost surely, 231223200133113 is an apocalyptic number.
It is an amenable number.
31223200133113 is a deficient number, since it is larger than the sum of its proper divisors (1).
31223200133113 is an equidigital number, since it uses as much as digits as its factorization.
31223200133113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 31223200133113 its reverse (31133100232213), we get a palindrome (62356300365326).
The spelling of 31223200133113 in words is "thirty-one trillion, two hundred twenty-three billion, two hundred million, one hundred thirty-three thousand, one hundred thirteen".
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