Base | Representation |
---|---|
bin | 100011011111110111000001… |
… | …0101100000100010100010011 |
3 | 1111221120001020020102200022221 |
4 | 1012333232002230010110103 |
5 | 311411233124112321003 |
6 | 3024030000451441511 |
7 | 122524512223064512 |
oct | 10677560254042423 |
9 | 1457501206380287 |
10 | 312242020042003 |
11 | 905431081a9a67 |
12 | 2b02a7188b6297 |
13 | 1052c3b0839a3c |
14 | 5716847098679 |
15 | 26171e8c0b7bd |
hex | 11bfb82b04513 |
312242020042003 has 2 divisors, whose sum is σ = 312242020042004. Its totient is φ = 312242020042002.
The previous prime is 312242020041983. The next prime is 312242020042009. The reversal of 312242020042003 is 300240020242213.
It is a strong prime.
It is an emirp because it is prime and its reverse (300240020242213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 312242020042003 - 29 = 312242020041491 is a prime.
It is not a weakly prime, because it can be changed into another prime (312242020042009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156121010021001 + 156121010021002.
It is an arithmetic number, because the mean of its divisors is an integer number (156121010021002).
Almost surely, 2312242020042003 is an apocalyptic number.
312242020042003 is a deficient number, since it is larger than the sum of its proper divisors (1).
312242020042003 is an equidigital number, since it uses as much as digits as its factorization.
312242020042003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 25.
Adding to 312242020042003 its reverse (300240020242213), we get a palindrome (612482040284216).
The spelling of 312242020042003 in words is "three hundred twelve trillion, two hundred forty-two billion, twenty million, forty-two thousand, three".
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