Base | Representation |
---|---|
bin | 101101011011111111100… |
… | …010001010010010111111 |
3 | 102001111112202022112000022 |
4 | 231123333202022102333 |
5 | 402124220422331142 |
6 | 10350232012122355 |
7 | 441405545001101 |
oct | 55337742122277 |
9 | 12044482275008 |
10 | 3122433402047 |
11 | aa4242287873 |
12 | 4251947663bb |
13 | 1985a0bc952b |
14 | ab1ab4b5571 |
15 | 5634d16c6d2 |
hex | 2d6ff88a4bf |
3122433402047 has 2 divisors, whose sum is σ = 3122433402048. Its totient is φ = 3122433402046.
The previous prime is 3122433402041. The next prime is 3122433402079. The reversal of 3122433402047 is 7402043342213.
3122433402047 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3122433402047 - 24 = 3122433402031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3122433401998 and 3122433402016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3122433402041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561216701023 + 1561216701024.
It is an arithmetic number, because the mean of its divisors is an integer number (1561216701024).
Almost surely, 23122433402047 is an apocalyptic number.
3122433402047 is a deficient number, since it is larger than the sum of its proper divisors (1).
3122433402047 is an equidigital number, since it uses as much as digits as its factorization.
3122433402047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 35.
The spelling of 3122433402047 in words is "three trillion, one hundred twenty-two billion, four hundred thirty-three million, four hundred two thousand, forty-seven".
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