Base | Representation |
---|---|
bin | 100011100000010010000100… |
… | …0101101011001101001111111 |
3 | 1111221202121011010222102022101 |
4 | 1013000210020231121221333 |
5 | 311413211102344111333 |
6 | 3024112404201325531 |
7 | 122531636455045102 |
oct | 10700441055315177 |
9 | 1457677133872271 |
10 | 312300103113343 |
11 | 90565803619164 |
12 | 2b039a287968a7 |
13 | 10534a090b6bc7 |
14 | 5719597118739 |
15 | 261899800a67d |
hex | 11c0908b59a7f |
312300103113343 has 2 divisors, whose sum is σ = 312300103113344. Its totient is φ = 312300103113342.
The previous prime is 312300103113293. The next prime is 312300103113373. The reversal of 312300103113343 is 343311301003213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312300103113343 - 217 = 312300102982271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312300103113373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156150051556671 + 156150051556672.
It is an arithmetic number, because the mean of its divisors is an integer number (156150051556672).
Almost surely, 2312300103113343 is an apocalyptic number.
312300103113343 is a deficient number, since it is larger than the sum of its proper divisors (1).
312300103113343 is an equidigital number, since it uses as much as digits as its factorization.
312300103113343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 28.
Adding to 312300103113343 its reverse (343311301003213), we get a palindrome (655611404116556).
The spelling of 312300103113343 in words is "three hundred twelve trillion, three hundred billion, one hundred three million, one hundred thirteen thousand, three hundred forty-three".
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