Base | Representation |
---|---|
bin | 1110001100111010101000… |
… | …01110010000000110000111 |
3 | 11002120120101202221011011220 |
4 | 13012131110032100012013 |
5 | 13043133241234400203 |
6 | 150230530312531423 |
7 | 6402205331004540 |
oct | 706352416200607 |
9 | 132516352834156 |
10 | 31230120231303 |
11 | 9a5068a780794 |
12 | 36047340b0b73 |
13 | 1456cabc97316 |
14 | 79d78dc994c7 |
15 | 392578e3c653 |
hex | 1c6754390187 |
31230120231303 has 64 divisors (see below), whose sum is σ = 51276093603840. Its totient is φ = 16500408307200.
The previous prime is 31230120231287. The next prime is 31230120231311. The reversal of 31230120231303 is 30313202103213.
It is not a de Polignac number, because 31230120231303 - 24 = 31230120231287 is a prime.
It is a super-3 number, since 3×312301202313033 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31230120231383) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 31335558 + ... + 32316828.
It is an arithmetic number, because the mean of its divisors is an integer number (801188962560).
Almost surely, 231230120231303 is an apocalyptic number.
31230120231303 is a deficient number, since it is larger than the sum of its proper divisors (20045973372537).
31230120231303 is a wasteful number, since it uses less digits than its factorization.
31230120231303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 982868.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 31230120231303 its reverse (30313202103213), we get a palindrome (61543322334516).
The spelling of 31230120231303 in words is "thirty-one trillion, two hundred thirty billion, one hundred twenty million, two hundred thirty-one thousand, three hundred three".
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