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3123033311131 is a prime number
BaseRepresentation
bin101101011100100011010…
…010101000011110011011
3102001120002120011001120021
4231130203102220132123
5402131433011424011
610350411322211311
7441426451101136
oct55344322503633
912046076131507
103123033311131
11aa451a9833a8
12425321653b37
13198668292916
14ab22703721d
1556385b6d471
hex2d7234a879b

3123033311131 has 2 divisors, whose sum is σ = 3123033311132. Its totient is φ = 3123033311130.

The previous prime is 3123033311051. The next prime is 3123033311143. The reversal of 3123033311131 is 1311133303213.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3123033311131 - 219 = 3123032786843 is a prime.

It is a super-2 number, since 2×31230333111312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3123033311096 and 3123033311105.

It is not a weakly prime, because it can be changed into another prime (3123033311231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561516655565 + 1561516655566.

It is an arithmetic number, because the mean of its divisors is an integer number (1561516655566).

Almost surely, 23123033311131 is an apocalyptic number.

3123033311131 is a deficient number, since it is larger than the sum of its proper divisors (1).

3123033311131 is an equidigital number, since it uses as much as digits as its factorization.

3123033311131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 3123033311131 its reverse (1311133303213), we get a palindrome (4434166614344).

The spelling of 3123033311131 in words is "three trillion, one hundred twenty-three billion, thirty-three million, three hundred eleven thousand, one hundred thirty-one".