Base | Representation |
---|---|
bin | 101101011100100011010… |
… | …010101000011110011011 |
3 | 102001120002120011001120021 |
4 | 231130203102220132123 |
5 | 402131433011424011 |
6 | 10350411322211311 |
7 | 441426451101136 |
oct | 55344322503633 |
9 | 12046076131507 |
10 | 3123033311131 |
11 | aa451a9833a8 |
12 | 425321653b37 |
13 | 198668292916 |
14 | ab22703721d |
15 | 56385b6d471 |
hex | 2d7234a879b |
3123033311131 has 2 divisors, whose sum is σ = 3123033311132. Its totient is φ = 3123033311130.
The previous prime is 3123033311051. The next prime is 3123033311143. The reversal of 3123033311131 is 1311133303213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3123033311131 - 219 = 3123032786843 is a prime.
It is a super-2 number, since 2×31230333111312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3123033311096 and 3123033311105.
It is not a weakly prime, because it can be changed into another prime (3123033311231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561516655565 + 1561516655566.
It is an arithmetic number, because the mean of its divisors is an integer number (1561516655566).
Almost surely, 23123033311131 is an apocalyptic number.
3123033311131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3123033311131 is an equidigital number, since it uses as much as digits as its factorization.
3123033311131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 3123033311131 its reverse (1311133303213), we get a palindrome (4434166614344).
The spelling of 3123033311131 in words is "three trillion, one hundred twenty-three billion, thirty-three million, three hundred eleven thousand, one hundred thirty-one".
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