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31230604404997 is a prime number
BaseRepresentation
bin1110001100111011100010…
…00101001110100100000101
311002120121122111222201121221
413012131301011032210011
513043140234211424442
6150231050330240341
76402223330264624
oct706356105164405
9132517574881557
1031230604404997
119a50909008638
12360484a2860b1
13145705839a92a
1479d7d82d16bb
153925a66cb467
hex1c677114e905

31230604404997 has 2 divisors, whose sum is σ = 31230604404998. Its totient is φ = 31230604404996.

The previous prime is 31230604404949. The next prime is 31230604405037. The reversal of 31230604404997 is 79940440603213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19714585692321 + 11516018712676 = 4440111^2 + 3393526^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31230604404997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31230604404907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15615302202498 + 15615302202499.

It is an arithmetic number, because the mean of its divisors is an integer number (15615302202499).

Almost surely, 231230604404997 is an apocalyptic number.

It is an amenable number.

31230604404997 is a deficient number, since it is larger than the sum of its proper divisors (1).

31230604404997 is an equidigital number, since it uses as much as digits as its factorization.

31230604404997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3919104, while the sum is 52.

The spelling of 31230604404997 in words is "thirty-one trillion, two hundred thirty billion, six hundred four million, four hundred four thousand, nine hundred ninety-seven".