Base | Representation |
---|---|
bin | 1110001100111011100010… |
… | …00101001110100110110011 |
3 | 11002120121122111222201212101 |
4 | 13012131301011032212303 |
5 | 13043140234211431141 |
6 | 150231050330241231 |
7 | 6402223330265263 |
oct | 706356105164663 |
9 | 132517574881771 |
10 | 31230604405171 |
11 | 9a50909008786 |
12 | 360484a286217 |
13 | 145705839aa32 |
14 | 79d7d82d17a3 |
15 | 3925a66cb531 |
hex | 1c677114e9b3 |
31230604405171 has 2 divisors, whose sum is σ = 31230604405172. Its totient is φ = 31230604405170.
The previous prime is 31230604405037. The next prime is 31230604405199. The reversal of 31230604405171 is 17150440603213.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (17150440603213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31230604405171 - 217 = 31230604274099 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31230604405171.
It is not a weakly prime, because it can be changed into another prime (31230604405471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15615302202585 + 15615302202586.
It is an arithmetic number, because the mean of its divisors is an integer number (15615302202586).
Almost surely, 231230604405171 is an apocalyptic number.
31230604405171 is a deficient number, since it is larger than the sum of its proper divisors (1).
31230604405171 is an equidigital number, since it uses as much as digits as its factorization.
31230604405171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 37.
The spelling of 31230604405171 in words is "thirty-one trillion, two hundred thirty billion, six hundred four million, four hundred five thousand, one hundred seventy-one".
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