Base | Representation |
---|---|
bin | 101101011100100111010… |
… | …001100001111111100101 |
3 | 102001120021012212212121101 |
4 | 231130213101201333211 |
5 | 402132102113200201 |
6 | 10350422110320101 |
7 | 441431222052133 |
oct | 55344721417745 |
9 | 12046235785541 |
10 | 3123100131301 |
11 | aa4554672387 |
12 | 42533bab9031 |
13 | 198679089c97 |
14 | ab231c6c753 |
15 | 5638b96bd01 |
hex | 2d727461fe5 |
3123100131301 has 2 divisors, whose sum is σ = 3123100131302. Its totient is φ = 3123100131300.
The previous prime is 3123100131289. The next prime is 3123100131341. The reversal of 3123100131301 is 1031310013213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2137587278401 + 985512852900 = 1462049^2 + 992730^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3123100131301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3123100131341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561550065650 + 1561550065651.
It is an arithmetic number, because the mean of its divisors is an integer number (1561550065651).
Almost surely, 23123100131301 is an apocalyptic number.
It is an amenable number.
3123100131301 is a deficient number, since it is larger than the sum of its proper divisors (1).
3123100131301 is an equidigital number, since it uses as much as digits as its factorization.
3123100131301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 3123100131301 its reverse (1031310013213), we get a palindrome (4154410144514).
The spelling of 3123100131301 in words is "three trillion, one hundred twenty-three billion, one hundred million, one hundred thirty-one thousand, three hundred one".
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