Base | Representation |
---|---|
bin | 1110001100111100101001… |
… | …01001000011111001011101 |
3 | 11002120200012002120221120011 |
4 | 13012132110221003321131 |
5 | 13043142444424013203 |
6 | 150231225441323221 |
7 | 6402244163256004 |
oct | 706362451037135 |
9 | 132520162527504 |
10 | 31231201001053 |
11 | 9a51094851029 |
12 | 3604996036511 |
13 | 1457121b74051 |
14 | 79d85362dc3b |
15 | 3925ddc7576d |
hex | 1c6794a43e5d |
31231201001053 has 2 divisors, whose sum is σ = 31231201001054. Its totient is φ = 31231201001052.
The previous prime is 31231201000949. The next prime is 31231201001057. The reversal of 31231201001053 is 35010010213213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30963014771364 + 268186229689 = 5564442^2 + 517867^2 .
It is a cyclic number.
It is not a de Polignac number, because 31231201001053 - 237 = 31093762047581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31231201001057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15615600500526 + 15615600500527.
It is an arithmetic number, because the mean of its divisors is an integer number (15615600500527).
Almost surely, 231231201001053 is an apocalyptic number.
It is an amenable number.
31231201001053 is a deficient number, since it is larger than the sum of its proper divisors (1).
31231201001053 is an equidigital number, since it uses as much as digits as its factorization.
31231201001053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 31231201001053 its reverse (35010010213213), we get a palindrome (66241211214266).
The spelling of 31231201001053 in words is "thirty-one trillion, two hundred thirty-one billion, two hundred one million, one thousand, fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •