Base | Representation |
---|---|
bin | 100011100000010111101001… |
… | …1110110100001001111100111 |
3 | 1111221210202010022112001002122 |
4 | 1013000233103312201033213 |
5 | 311413410140402310114 |
6 | 3024122110522300155 |
7 | 122532543004155665 |
oct | 10700572366411747 |
9 | 1457722108461078 |
10 | 312312101213159 |
11 | 9056a9001a2133 |
12 | 2b04021695765b |
13 | 10535b9ba34858 |
14 | 5719db479dc35 |
15 | 2618e4b502e8e |
hex | 11c0bd3da13e7 |
312312101213159 has 2 divisors, whose sum is σ = 312312101213160. Its totient is φ = 312312101213158.
The previous prime is 312312101213149. The next prime is 312312101213269. The reversal of 312312101213159 is 951312101213213.
It is a weak prime.
It is an emirp because it is prime and its reverse (951312101213213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 312312101213159 - 216 = 312312101147623 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312312101213149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156156050606579 + 156156050606580.
It is an arithmetic number, because the mean of its divisors is an integer number (156156050606580).
Almost surely, 2312312101213159 is an apocalyptic number.
312312101213159 is a deficient number, since it is larger than the sum of its proper divisors (1).
312312101213159 is an equidigital number, since it uses as much as digits as its factorization.
312312101213159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 35.
The spelling of 312312101213159 in words is "three hundred twelve trillion, three hundred twelve billion, one hundred one million, two hundred thirteen thousand, one hundred fifty-nine".
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