Base | Representation |
---|---|
bin | 1110001100111100110110… |
… | …01001001111011010000111 |
3 | 11002120200110200212202022201 |
4 | 13012132123021033122013 |
5 | 13043143210341200403 |
6 | 150231244335535331 |
7 | 6402246656506021 |
oct | 706363311173207 |
9 | 132520420782281 |
10 | 31231310100103 |
11 | 9a51140397833 |
12 | 3604a0668a547 |
13 | 145713b6522b9 |
14 | 79d863d0d011 |
15 | 3925e862621d |
hex | 1c679b24f687 |
31231310100103 has 2 divisors, whose sum is σ = 31231310100104. Its totient is φ = 31231310100102.
The previous prime is 31231310100091. The next prime is 31231310100157. The reversal of 31231310100103 is 30100101313213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31231310100103 - 225 = 31231276545671 is a prime.
It is a super-2 number, since 2×312313101001032 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31231310110103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15615655050051 + 15615655050052.
It is an arithmetic number, because the mean of its divisors is an integer number (15615655050052).
Almost surely, 231231310100103 is an apocalyptic number.
31231310100103 is a deficient number, since it is larger than the sum of its proper divisors (1).
31231310100103 is an equidigital number, since it uses as much as digits as its factorization.
31231310100103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 31231310100103 its reverse (30100101313213), we get a palindrome (61331411413316).
The spelling of 31231310100103 in words is "thirty-one trillion, two hundred thirty-one billion, three hundred ten million, one hundred thousand, one hundred three".
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