Base | Representation |
---|---|
bin | 100011100000011000001000… |
… | …0100110011100100101101011 |
3 | 1111221210211202100022121021102 |
4 | 1013000300100212130211223 |
5 | 311413414232311104323 |
6 | 3024122400011232015 |
7 | 122532610161202151 |
oct | 10700602046344553 |
9 | 1457724670277242 |
10 | 312313120409963 |
11 | 90570283537842 |
12 | 2b04046014860b |
13 | 10536001c3369a |
14 | 571a06dca73d1 |
15 | 2618eaac27328 |
hex | 11c0c1099c96b |
312313120409963 has 2 divisors, whose sum is σ = 312313120409964. Its totient is φ = 312313120409962.
The previous prime is 312313120409957. The next prime is 312313120409977. The reversal of 312313120409963 is 369904021313213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312313120409963 - 238 = 312038242503019 is a prime.
It is a super-2 number, since 2×3123131204099632 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (312313120709963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156156560204981 + 156156560204982.
It is an arithmetic number, because the mean of its divisors is an integer number (156156560204982).
Almost surely, 2312313120409963 is an apocalyptic number.
312313120409963 is a deficient number, since it is larger than the sum of its proper divisors (1).
312313120409963 is an equidigital number, since it uses as much as digits as its factorization.
312313120409963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 629856, while the sum is 47.
The spelling of 312313120409963 in words is "three hundred twelve trillion, three hundred thirteen billion, one hundred twenty million, four hundred nine thousand, nine hundred sixty-three".
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