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312320132147 is a prime number
BaseRepresentation
bin1001000101101111011…
…10110000010000110011
31002212011010102120211202
410202313232300100303
520104112423212042
6355251120201415
731364404215062
oct4426756602063
91085133376752
10312320132147
111104aa6329a1
125064346926b
13235b43bc82a
141118b4941d9
1581ce0b8632
hex48b7bb0433

312320132147 has 2 divisors, whose sum is σ = 312320132148. Its totient is φ = 312320132146.

The previous prime is 312320132119. The next prime is 312320132149. The reversal of 312320132147 is 741231023213.

It is a strong prime.

It is an emirp because it is prime and its reverse (741231023213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 312320132147 - 212 = 312320128051 is a prime.

Together with 312320132149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (312320132149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156160066073 + 156160066074.

It is an arithmetic number, because the mean of its divisors is an integer number (156160066074).

Almost surely, 2312320132147 is an apocalyptic number.

312320132147 is a deficient number, since it is larger than the sum of its proper divisors (1).

312320132147 is an equidigital number, since it uses as much as digits as its factorization.

312320132147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 29.

The spelling of 312320132147 in words is "three hundred twelve billion, three hundred twenty million, one hundred thirty-two thousand, one hundred forty-seven".