Base | Representation |
---|---|
bin | 11101000101100101… |
… | …000011111100100111 |
3 | 2222121121201210200102 |
4 | 131011211003330213 |
5 | 1002430410130341 |
6 | 22203044334315 |
7 | 2153650410215 |
oct | 350545037447 |
9 | 88547653612 |
10 | 31232114471 |
11 | 12277794958 |
12 | 60776a439b |
13 | 2c39721b0c |
14 | 1723d37cb5 |
15 | c2bda9c9b |
hex | 745943f27 |
31232114471 has 2 divisors, whose sum is σ = 31232114472. Its totient is φ = 31232114470.
The previous prime is 31232114423. The next prime is 31232114489. The reversal of 31232114471 is 17441123213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31232114471 - 222 = 31227920167 is a prime.
It is a super-3 number, since 3×312321144713 (a number of 32 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31232114491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15616057235 + 15616057236.
It is an arithmetic number, because the mean of its divisors is an integer number (15616057236).
Almost surely, 231232114471 is an apocalyptic number.
31232114471 is a deficient number, since it is larger than the sum of its proper divisors (1).
31232114471 is an equidigital number, since it uses as much as digits as its factorization.
31232114471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4032, while the sum is 29.
Adding to 31232114471 its reverse (17441123213), we get a palindrome (48673237684).
The spelling of 31232114471 in words is "thirty-one billion, two hundred thirty-two million, one hundred fourteen thousand, four hundred seventy-one".
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