Base | Representation |
---|---|
bin | 101101011100111011100… |
… | …110100110101110000000 |
3 | 102001121010222122221220102 |
4 | 231130323212212232000 |
5 | 402133301421400000 |
6 | 10350520012501532 |
7 | 441442533100412 |
oct | 55347346465600 |
9 | 12047128587812 |
10 | 3123441200000 |
11 | aa470a147340 |
12 | 42541617a8a8 |
13 | 198701936b94 |
14 | ab2652929b2 |
15 | 563ab88e3d5 |
hex | 2d73b9a6b80 |
3123441200000 has 384 divisors, whose sum is σ = 8547371683200. Its totient is φ = 1127404800000.
The previous prime is 3123441199997. The next prime is 3123441200023. The reversal of 3123441200000 is 21443213.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 611597447 + ... + 611602553.
It is an arithmetic number, because the mean of its divisors is an integer number (22258780425).
Almost surely, 23123441200000 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 3123441200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4273685841600).
3123441200000 is an abundant number, since it is smaller than the sum of its proper divisors (5423930483200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3123441200000 is an equidigital number, since it uses as much as digits as its factorization.
3123441200000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5296 (or 5264 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 3123441200000 its reverse (21443213), we get a palindrome (3123462643213).
The spelling of 3123441200000 in words is "three trillion, one hundred twenty-three billion, four hundred forty-one million, two hundred thousand".
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