Base | Representation |
---|---|
bin | 1110001101001101000111… |
… | …00100100010110111000011 |
3 | 11002121112000012101020210021 |
4 | 13012212203210202313003 |
5 | 13043314101100104422 |
6 | 150235251002114311 |
7 | 6403006230432664 |
oct | 706464344426703 |
9 | 132545005336707 |
10 | 31240041409987 |
11 | 9a54910a4a113 |
12 | 36066427ab997 |
13 | 1457c00547a57 |
14 | 7a005178136b |
15 | 392959e2adc7 |
hex | 1c69a3922dc3 |
31240041409987 has 2 divisors, whose sum is σ = 31240041409988. Its totient is φ = 31240041409986.
The previous prime is 31240041409979. The next prime is 31240041409999. The reversal of 31240041409987 is 78990414004213.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31240041409987 - 23 = 31240041409979 is a prime.
It is a super-3 number, since 3×312400414099873 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (31240041400987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15620020704993 + 15620020704994.
It is an arithmetic number, because the mean of its divisors is an integer number (15620020704994).
Almost surely, 231240041409987 is an apocalyptic number.
31240041409987 is a deficient number, since it is larger than the sum of its proper divisors (1).
31240041409987 is an equidigital number, since it uses as much as digits as its factorization.
31240041409987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1741824, while the sum is 52.
The spelling of 31240041409987 in words is "thirty-one trillion, two hundred forty billion, forty-one million, four hundred nine thousand, nine hundred eighty-seven".
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