Base | Representation |
---|---|
bin | 101101011101011101110… |
… | …001001101000110110111 |
3 | 102001122121221020202000001 |
4 | 231131131301031012313 |
5 | 402140440141412043 |
6 | 10351052530332131 |
7 | 441462663204232 |
oct | 55353561150667 |
9 | 12048557222001 |
10 | 3124014404023 |
11 | aa4983762a77 |
12 | 42555612a047 |
13 | 19879360cc66 |
14 | ab2bb462419 |
15 | 563e1d6774d |
hex | 2d75dc4d1b7 |
3124014404023 has 2 divisors, whose sum is σ = 3124014404024. Its totient is φ = 3124014404022.
The previous prime is 3124014403949. The next prime is 3124014404057. The reversal of 3124014404023 is 3204044104213.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3124014404023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3124014403982 and 3124014404000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3124014402023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562007202011 + 1562007202012.
It is an arithmetic number, because the mean of its divisors is an integer number (1562007202012).
Almost surely, 23124014404023 is an apocalyptic number.
3124014404023 is a deficient number, since it is larger than the sum of its proper divisors (1).
3124014404023 is an equidigital number, since it uses as much as digits as its factorization.
3124014404023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 3124014404023 its reverse (3204044104213), we get a palindrome (6328058508236).
The spelling of 3124014404023 in words is "three trillion, one hundred twenty-four billion, fourteen million, four hundred four thousand, twenty-three".
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