312411404114213 has 4 divisors (see below), whose sum is σ = 312474504786528. Its totient is φ = 312348303441900.

The previous prime is 312411404114189. The next prime is 312411404114237.

312411404114213 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (312411404114189) and next prime (312411404114237).

It is a cyclic number.

It is not a de Polignac number, because 312411404114213 - 2¹⁸ = 312411403852069 is a prime.

It is a super-2 number, since 2×312411404114213² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 312411404114213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312411404114713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31550328731 + ... + 31550338632.

It is an arithmetic number, because the mean of its divisors is an integer number (78118626196632).

Almost surely, 2^{312411404114213} is an apocalyptic number.

It is an amenable number.

312411404114213 is a deficient number, since it is larger than the sum of its proper divisors (63100672315).

312411404114213 is an equidigital number, since it uses as much as digits as its factorization.

312411404114213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63100672314.

The product of its (nonzero) digits is 9216, while the sum is 32.

It can be divided in two parts, 31241140 and 4114213, that added together give a palindrome (35355353).

The spelling of 312411404114213 in words is "three hundred twelve trillion, four hundred eleven billion, four hundred four million, one hundred fourteen thousand, two hundred thirteen".