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312412323411431 is a prime number
BaseRepresentation
bin100011100001000110010100…
…1100011110111010111100111
31111222011022210222021020001222
41013002030221203313113213
5311422030414243131211
63024240123504010555
7122543021416614605
oct10702145143672747
91458138728236058
10312412323411431
11905a935aaa2071
122b057727000a5b
13105424815a1459
145720ba1140875
15261b864ece1db
hex11c23298f75e7

312412323411431 has 2 divisors, whose sum is σ = 312412323411432. Its totient is φ = 312412323411430.

The previous prime is 312412323411343. The next prime is 312412323411437. The reversal of 312412323411431 is 134114323214213.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-312412323411431 is a prime.

It is a super-2 number, since 2×3124123234114312 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 312412323411391 and 312412323411400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312412323411437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156206161705715 + 156206161705716.

It is an arithmetic number, because the mean of its divisors is an integer number (156206161705716).

Almost surely, 2312412323411431 is an apocalyptic number.

312412323411431 is a deficient number, since it is larger than the sum of its proper divisors (1).

312412323411431 is an equidigital number, since it uses as much as digits as its factorization.

312412323411431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 41472, while the sum is 35.

Adding to 312412323411431 its reverse (134114323214213), we get a palindrome (446526646625644).

The spelling of 312412323411431 in words is "three hundred twelve trillion, four hundred twelve billion, three hundred twenty-three million, four hundred eleven thousand, four hundred thirty-one".