Base | Representation |
---|---|
bin | 101101011101100101010… |
… | …001111001010100000011 |
3 | 102001122221201100201111001 |
4 | 231131211101321110003 |
5 | 402141214421223321 |
6 | 10351113231232431 |
7 | 441466053236665 |
oct | 55354521712403 |
9 | 12048851321431 |
10 | 3124140414211 |
11 | aa4a388aa323 |
12 | 425590378717 |
13 | 1987b375c6bb |
14 | ab2d00a4535 |
15 | 563ece58c91 |
hex | 2d765479503 |
3124140414211 has 2 divisors, whose sum is σ = 3124140414212. Its totient is φ = 3124140414210.
The previous prime is 3124140414193. The next prime is 3124140414253. The reversal of 3124140414211 is 1124140414213.
It is a happy number.
3124140414211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3124140414211 - 25 = 3124140414179 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3124140414211.
It is not a weakly prime, because it can be changed into another prime (3124140411211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562070207105 + 1562070207106.
It is an arithmetic number, because the mean of its divisors is an integer number (1562070207106).
Almost surely, 23124140414211 is an apocalyptic number.
3124140414211 is a deficient number, since it is larger than the sum of its proper divisors (1).
3124140414211 is an equidigital number, since it uses as much as digits as its factorization.
3124140414211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3072, while the sum is 28.
Adding to 3124140414211 its reverse (1124140414213), we get a palindrome (4248280828424).
The spelling of 3124140414211 in words is "three trillion, one hundred twenty-four billion, one hundred forty million, four hundred fourteen thousand, two hundred eleven".
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