Base | Representation |
---|---|
bin | 100011100001001011011000… |
… | …1101010100111101011001111 |
3 | 1111222012100212202111111221111 |
4 | 1013002112301222213223033 |
5 | 311422220201341140002 |
6 | 3024245122450512451 |
7 | 122543555031216013 |
oct | 10702266152475317 |
9 | 1458170782444844 |
10 | 312423196818127 |
11 | 90602a2a82549a |
12 | 2b059860595727 |
13 | 105434c5203b05 |
14 | 572151329a543 |
15 | 261bc9e8b43d7 |
hex | 11c25b1aa7acf |
312423196818127 has 2 divisors, whose sum is σ = 312423196818128. Its totient is φ = 312423196818126.
The previous prime is 312423196818071. The next prime is 312423196818191. The reversal of 312423196818127 is 721818691324213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312423196818127 - 231 = 312421049334479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312423196878127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156211598409063 + 156211598409064.
It is an arithmetic number, because the mean of its divisors is an integer number (156211598409064).
Almost surely, 2312423196818127 is an apocalyptic number.
312423196818127 is a deficient number, since it is larger than the sum of its proper divisors (1).
312423196818127 is an equidigital number, since it uses as much as digits as its factorization.
312423196818127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6967296, while the sum is 58.
The spelling of 312423196818127 in words is "three hundred twelve trillion, four hundred twenty-three billion, one hundred ninety-six million, eight hundred eighteen thousand, one hundred twenty-seven".
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