Base | Representation |
---|---|
bin | 11101000110001111… |
… | …011100000001011011 |
3 | 2222122101122011220021 |
4 | 131012033130001123 |
5 | 1002441231120011 |
6 | 22204122411311 |
7 | 2154144005041 |
oct | 350617340133 |
9 | 88571564807 |
10 | 31243223131 |
11 | 12282a91a6a |
12 | 607b360b37 |
13 | 2c3bb111a3 |
14 | 17255ca391 |
15 | c2cd51471 |
hex | 7463dc05b |
31243223131 has 2 divisors, whose sum is σ = 31243223132. Its totient is φ = 31243223130.
The previous prime is 31243223087. The next prime is 31243223171. The reversal of 31243223131 is 13132234213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31243223131 - 27 = 31243223003 is a prime.
It is a super-2 number, since 2×312432231312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31243223096 and 31243223105.
It is not a weakly prime, because it can be changed into another prime (31243223171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15621611565 + 15621611566.
It is an arithmetic number, because the mean of its divisors is an integer number (15621611566).
Almost surely, 231243223131 is an apocalyptic number.
31243223131 is a deficient number, since it is larger than the sum of its proper divisors (1).
31243223131 is an equidigital number, since it uses as much as digits as its factorization.
31243223131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592, while the sum is 25.
Adding to 31243223131 its reverse (13132234213), we get a palindrome (44375457344).
The spelling of 31243223131 in words is "thirty-one billion, two hundred forty-three million, two hundred twenty-three thousand, one hundred thirty-one".
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