Base | Representation |
---|---|
bin | 100011100001010000000000… |
… | …0001000100111111110001100 |
3 | 1111222020022110011011221112001 |
4 | 1013002200000020213332030 |
5 | 311422400443412203400 |
6 | 3024253441451522044 |
7 | 122544355361346442 |
oct | 10702400010477614 |
9 | 1458208404157461 |
10 | 312433103241100 |
11 | 90607153735716 |
12 | 2b05b766159324 |
13 | 105444136b915a |
14 | 5721bb2c20b92 |
15 | 261c17e43aa6a |
hex | 11c2800227f8c |
312433103241100 has 72 divisors (see below), whose sum is σ = 684759510898848. Its totient is φ = 123728422540800.
The previous prime is 312433103241047. The next prime is 312433103241157. The reversal of 312433103241100 is 1142301334213.
It is a super-2 number, since 2×3124331032411002 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 25460056 + ... + 35680255.
It is an arithmetic number, because the mean of its divisors is an integer number (9510548762484).
Almost surely, 2312433103241100 is an apocalyptic number.
It is an amenable number.
312433103241100 is an abundant number, since it is smaller than the sum of its proper divisors (372326407657748).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312433103241100 is a wasteful number, since it uses less digits than its factorization.
312433103241100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61140835 (or 61140828 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 312433103241100 its reverse (1142301334213), we get a palindrome (313575404575313).
The spelling of 312433103241100 in words is "three hundred twelve trillion, four hundred thirty-three billion, one hundred three million, two hundred forty-one thousand, one hundred".
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