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3124340434214 = 21562170217107
BaseRepresentation
bin101101011101110001001…
…100111010010100100110
3102001200110122201210100022
4231131301030322110212
5402142122122343324
610351145134315142
7441504032336456
oct55356114722446
912050418653308
103124340434214
11aa50307a630a
12425627358ab2
13198816022b2c
14ab30c88dd66
15564107b905e
hex2d77133a526

3124340434214 has 4 divisors (see below), whose sum is σ = 4686510651324. Its totient is φ = 1562170217106.

The previous prime is 3124340434181. The next prime is 3124340434219. The reversal of 3124340434214 is 4124340434213.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3124340434219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 781085108552 + ... + 781085108555.

It is an arithmetic number, because the mean of its divisors is an integer number (1171627662831).

Almost surely, 23124340434214 is an apocalyptic number.

3124340434214 is a deficient number, since it is larger than the sum of its proper divisors (1562170217110).

3124340434214 is a wasteful number, since it uses less digits than its factorization.

3124340434214 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1562170217109.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 3124340434214 its reverse (4124340434213), we get a palindrome (7248680868427).

Subtracting 3124340434214 from its reverse (4124340434213), we obtain a palindrome (999999999999).

The spelling of 3124340434214 in words is "three trillion, one hundred twenty-four billion, three hundred forty million, four hundred thirty-four thousand, two hundred fourteen".

Divisors: 1 2 1562170217107 3124340434214