Base | Representation |
---|---|
bin | 101101011101110001001… |
… | …100111010010100100101 |
3 | 102001200110122201210100021 |
4 | 231131301030322110211 |
5 | 402142122122343323 |
6 | 10351145134315141 |
7 | 441504032336455 |
oct | 55356114722445 |
9 | 12050418653307 |
10 | 3124340434213 |
11 | aa50307a6309 |
12 | 425627358ab1 |
13 | 198816022b2b |
14 | ab30c88dd65 |
15 | 564107b905d |
hex | 2d77133a525 |
3124340434213 has 8 divisors (see below), whose sum is σ = 3146067691200. Its totient is φ = 3102673448160.
The previous prime is 3124340434181. The next prime is 3124340434219.
3124340434213 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3124340434213 - 25 = 3124340434181 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3124340434219) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14963695 + ... + 15171052.
It is an arithmetic number, because the mean of its divisors is an integer number (393258461400).
Almost surely, 23124340434213 is an apocalyptic number.
It is an amenable number.
3124340434213 is a deficient number, since it is larger than the sum of its proper divisors (21727256987).
3124340434213 is a wasteful number, since it uses less digits than its factorization.
3124340434213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30135467.
The product of its (nonzero) digits is 82944, while the sum is 34.
It can be divided in two parts, 3124340 and 434213, that added together give a palindrome (3558553).
The spelling of 3124340434213 in words is "three trillion, one hundred twenty-four billion, three hundred forty million, four hundred thirty-four thousand, two hundred thirteen".
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