Base | Representation |
---|---|
bin | 1001000101111101011… |
… | …01011010001011010010 |
3 | 1002212110021202021020202 |
4 | 10202332231122023102 |
5 | 20104332412020200 |
6 | 355310501535202 |
7 | 31400325360164 |
oct | 4427655321322 |
9 | 1085407667222 |
10 | 312437220050 |
11 | 11055a73585a |
12 | 50676714502 |
13 | 23602737107 |
14 | 1119cc52934 |
15 | 81d94e61d5 |
hex | 48beb5a2d2 |
312437220050 has 54 divisors (see below), whose sum is σ = 586422366957. Its totient is φ = 123847649280.
The previous prime is 312437220037. The next prime is 312437220061. The reversal of 312437220050 is 50022734213.
It can be written as a sum of positive squares in 14 ways, for example, as 113850231889 + 198586988161 = 337417^2 + 445631^2 .
It is an ABA number since it can be written as A⋅BA, here for A=2, B=395245.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 312437219995 and 312437220022.
It is an unprimeable number.
It is a polite number, since it can be written in 26 ways as a sum of consecutive naturals, for example, 541485362 + ... + 541485938.
Almost surely, 2312437220050 is an apocalyptic number.
312437220050 is a deficient number, since it is larger than the sum of its proper divisors (273985146907).
312437220050 is an frugal number, since it uses more digits than its factorization.
312437220050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1440 (or 721 counting only the distinct ones).
The product of its (nonzero) digits is 10080, while the sum is 29.
Adding to 312437220050 its reverse (50022734213), we get a palindrome (362459954263).
The spelling of 312437220050 in words is "three hundred twelve billion, four hundred thirty-seven million, two hundred twenty thousand, fifty".
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