Base | Representation |
---|---|
bin | 101101011101110110001… |
… | …000010001011101000011 |
3 | 102001200200102021212102012 |
4 | 231131312020101131003 |
5 | 402142304303314243 |
6 | 10351201250243135 |
7 | 441506055123263 |
oct | 55356610213503 |
9 | 12050612255365 |
10 | 3124423104323 |
11 | aa5073430614 |
12 | 42564ab864ab |
13 | 19882a1a9661 |
14 | ab31984d7a3 |
15 | 56417b98d18 |
hex | 2d776211743 |
3124423104323 has 2 divisors, whose sum is σ = 3124423104324. Its totient is φ = 3124423104322.
The previous prime is 3124423104317. The next prime is 3124423104401. The reversal of 3124423104323 is 3234013244213.
3124423104323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3124423104323 - 28 = 3124423104067 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3124423104323.
It is not a weakly prime, because it can be changed into another prime (3124423154323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562211552161 + 1562211552162.
It is an arithmetic number, because the mean of its divisors is an integer number (1562211552162).
Almost surely, 23124423104323 is an apocalyptic number.
3124423104323 is a deficient number, since it is larger than the sum of its proper divisors (1).
3124423104323 is an equidigital number, since it uses as much as digits as its factorization.
3124423104323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 3124423104323 its reverse (3234013244213), we get a palindrome (6358436348536).
The spelling of 3124423104323 in words is "three trillion, one hundred twenty-four billion, four hundred twenty-three million, one hundred four thousand, three hundred twenty-three".
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