Base | Representation |
---|---|
bin | 1001000101111110010… |
… | …00110011111001101011 |
3 | 1002212110210021012211022 |
4 | 10202333020303321223 |
5 | 20104341231401212 |
6 | 355311315523055 |
7 | 31400443415501 |
oct | 4427710637153 |
9 | 1085423235738 |
10 | 312444403307 |
11 | 1105637a1733 |
12 | 50678bb948b |
13 | 2360408086a |
14 | 1119dba2671 |
15 | 81d9e64772 |
hex | 48bf233e6b |
312444403307 has 2 divisors, whose sum is σ = 312444403308. Its totient is φ = 312444403306.
The previous prime is 312444403303. The next prime is 312444403309. The reversal of 312444403307 is 703304444213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312444403307 - 22 = 312444403303 is a prime.
Together with 312444403309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (312444403303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156222201653 + 156222201654.
It is an arithmetic number, because the mean of its divisors is an integer number (156222201654).
Almost surely, 2312444403307 is an apocalyptic number.
312444403307 is a deficient number, since it is larger than the sum of its proper divisors (1).
312444403307 is an equidigital number, since it uses as much as digits as its factorization.
312444403307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 35.
The spelling of 312444403307 in words is "three hundred twelve billion, four hundred forty-four million, four hundred three thousand, three hundred seven".
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