Base | Representation |
---|---|
bin | 100011100001011010001111… |
… | …1010100101011011111011100 |
3 | 1111222022102020020110201101222 |
4 | 1013002310133110223133130 |
5 | 311423231021420101140 |
6 | 3024311520355152512 |
7 | 122546064455132525 |
oct | 10702643724533734 |
9 | 1458272206421358 |
10 | 312455101331420 |
11 | 90615512017553 |
12 | 2b063a852a5738 |
13 | 1054650b01cb48 |
14 | 5722c9c62584c |
15 | 261ca1a7dd5b5 |
hex | 11c2d1f52b7dc |
312455101331420 has 12 divisors (see below), whose sum is σ = 656155712796024. Its totient is φ = 124982040532560.
The previous prime is 312455101331407. The next prime is 312455101331423. The reversal of 312455101331420 is 24133101554213.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312455101331423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7811377533266 + ... + 7811377533305.
It is an arithmetic number, because the mean of its divisors is an integer number (54679642733002).
Almost surely, 2312455101331420 is an apocalyptic number.
It is an amenable number.
312455101331420 is an abundant number, since it is smaller than the sum of its proper divisors (343700611464604).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312455101331420 is a wasteful number, since it uses less digits than its factorization.
312455101331420 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15622755066580 (or 15622755066578 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 312455101331420 its reverse (24133101554213), we get a palindrome (336588202885633).
The spelling of 312455101331420 in words is "three hundred twelve trillion, four hundred fifty-five billion, one hundred one million, three hundred thirty-one thousand, four hundred twenty".
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