Base | Representation |
---|---|
bin | 1001000110000011111… |
… | …00111001000101000111 |
3 | 1002212121002002120211121 |
4 | 10203001330321011013 |
5 | 20104440323013224 |
6 | 355320123414411 |
7 | 31401555601561 |
oct | 4430174710507 |
9 | 1085532076747 |
10 | 312491610439 |
11 | 110588405098 |
12 | 50690984407 |
13 | 23610a9b988 |
14 | 111a6170331 |
15 | 81de18bbe4 |
hex | 48c1f39147 |
312491610439 has 2 divisors, whose sum is σ = 312491610440. Its totient is φ = 312491610438.
The previous prime is 312491610401. The next prime is 312491610479. The reversal of 312491610439 is 934016194213.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312491610439 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 312491610395 and 312491610404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312491610479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156245805219 + 156245805220.
It is an arithmetic number, because the mean of its divisors is an integer number (156245805220).
Almost surely, 2312491610439 is an apocalyptic number.
312491610439 is a deficient number, since it is larger than the sum of its proper divisors (1).
312491610439 is an equidigital number, since it uses as much as digits as its factorization.
312491610439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 139968, while the sum is 43.
The spelling of 312491610439 in words is "three hundred twelve billion, four hundred ninety-one million, six hundred ten thousand, four hundred thirty-nine".
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