Base | Representation |
---|---|
bin | 1001000110000100001… |
… | …10100010001001001011 |
3 | 1002212121020211222220102 |
4 | 10203002012202021023 |
5 | 20104441444403211 |
6 | 355320253520015 |
7 | 31401616226423 |
oct | 4430206421113 |
9 | 1085536758812 |
10 | 312494137931 |
11 | 110589881028 |
12 | 506917a300b |
13 | 23611475231 |
14 | 111a662b483 |
15 | 81de4daa3b |
hex | 48c21a224b |
312494137931 has 2 divisors, whose sum is σ = 312494137932. Its totient is φ = 312494137930.
The previous prime is 312494137913. The next prime is 312494137939. The reversal of 312494137931 is 139731494213.
Together with previous prime (312494137913) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312494137931 - 210 = 312494136907 is a prime.
It is a super-2 number, since 2×3124941379312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (312494137939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156247068965 + 156247068966.
It is an arithmetic number, because the mean of its divisors is an integer number (156247068966).
Almost surely, 2312494137931 is an apocalyptic number.
312494137931 is a deficient number, since it is larger than the sum of its proper divisors (1).
312494137931 is an equidigital number, since it uses as much as digits as its factorization.
312494137931 is an evil number, because the sum of its binary digits is even.
The product of its digits is 489888, while the sum is 47.
The spelling of 312494137931 in words is "three hundred twelve billion, four hundred ninety-four million, one hundred thirty-seven thousand, nine hundred thirty-one".
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