Base | Representation |
---|---|
bin | 101101011110010110111… |
… | …101011011110001101011 |
3 | 102001202002210201202022221 |
4 | 231132112331123301223 |
5 | 402144421310124042 |
6 | 10351332044054511 |
7 | 441525523655134 |
oct | 55362675336153 |
9 | 12052083652287 |
10 | 3124973911147 |
11 | aa5326339970 |
12 | 425783534437 |
13 | 1988b734015a |
14 | ab36ca6cc8b |
15 | 5644b1ead67 |
hex | 2d796f5bc6b |
3124973911147 has 24 divisors (see below), whose sum is σ = 3713992584192. Its totient is φ = 2604546759600.
The previous prime is 3124973911133. The next prime is 3124973911217. The reversal of 3124973911147 is 7411193794213.
It is a de Polignac number, because none of the positive numbers 2k-3124973911147 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3124973911094 and 3124973911103.
It is not an unprimeable number, because it can be changed into a prime (3124973911547) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12569623 + ... + 12815824.
It is an arithmetic number, because the mean of its divisors is an integer number (154749691008).
Almost surely, 23124973911147 is an apocalyptic number.
3124973911147 is a deficient number, since it is larger than the sum of its proper divisors (589018673045).
3124973911147 is a wasteful number, since it uses less digits than its factorization.
3124973911147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25385527 (or 25385508 counting only the distinct ones).
The product of its digits is 1143072, while the sum is 52.
The spelling of 3124973911147 in words is "three trillion, one hundred twenty-four billion, nine hundred seventy-three million, nine hundred eleven thousand, one hundred forty-seven".
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