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3124973911217 is a prime number
BaseRepresentation
bin101101011110010110111…
…101011011110010110001
3102001202002210201202102112
4231132112331123302301
5402144421310124332
610351332044055105
7441525523655264
oct55362675336261
912052083652375
103124973911217
11aa5326339a24
12425783534495
131988b73401b2
14ab36ca6ccdb
155644b1eadb2
hex2d796f5bcb1

3124973911217 has 2 divisors, whose sum is σ = 3124973911218. Its totient is φ = 3124973911216.

The previous prime is 3124973911133. The next prime is 3124973911219. The reversal of 3124973911217 is 7121193794213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3109805279296 + 15168631921 = 1763464^2 + 123161^2 .

It is a cyclic number.

It is not a de Polignac number, because 3124973911217 - 230 = 3123900169393 is a prime.

Together with 3124973911219, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3124973911219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562486955608 + 1562486955609.

It is an arithmetic number, because the mean of its divisors is an integer number (1562486955609).

Almost surely, 23124973911217 is an apocalyptic number.

It is an amenable number.

3124973911217 is a deficient number, since it is larger than the sum of its proper divisors (1).

3124973911217 is an equidigital number, since it uses as much as digits as its factorization.

3124973911217 is an evil number, because the sum of its binary digits is even.

The product of its digits is 571536, while the sum is 50.

The spelling of 3124973911217 in words is "three trillion, one hundred twenty-four billion, nine hundred seventy-three million, nine hundred eleven thousand, two hundred seventeen".