Base | Representation |
---|---|
bin | 101101011110010110111… |
… | …101011011110001011101 |
3 | 102001202002210201202022102 |
4 | 231132112331123301131 |
5 | 402144421310124013 |
6 | 10351332044054445 |
7 | 441525523655114 |
oct | 55362675336135 |
9 | 12052083652272 |
10 | 3124973911133 |
11 | aa5326339958 |
12 | 425783534425 |
13 | 1988b7340149 |
14 | ab36ca6cc7b |
15 | 5644b1ead58 |
hex | 2d796f5bc5d |
3124973911133 has 2 divisors, whose sum is σ = 3124973911134. Its totient is φ = 3124973911132.
The previous prime is 3124973911123. The next prime is 3124973911217. The reversal of 3124973911133 is 3311193794213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2978375285209 + 146598625924 = 1725797^2 + 382882^2 .
It is an emirp because it is prime and its reverse (3311193794213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3124973911133 - 218 = 3124973648989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3124973911123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562486955566 + 1562486955567.
It is an arithmetic number, because the mean of its divisors is an integer number (1562486955567).
Almost surely, 23124973911133 is an apocalyptic number.
It is an amenable number.
3124973911133 is a deficient number, since it is larger than the sum of its proper divisors (1).
3124973911133 is an equidigital number, since it uses as much as digits as its factorization.
3124973911133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 367416, while the sum is 47.
The spelling of 3124973911133 in words is "three trillion, one hundred twenty-four billion, nine hundred seventy-three million, nine hundred eleven thousand, one hundred thirty-three".
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