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3124973911133 is a prime number
BaseRepresentation
bin101101011110010110111…
…101011011110001011101
3102001202002210201202022102
4231132112331123301131
5402144421310124013
610351332044054445
7441525523655114
oct55362675336135
912052083652272
103124973911133
11aa5326339958
12425783534425
131988b7340149
14ab36ca6cc7b
155644b1ead58
hex2d796f5bc5d

3124973911133 has 2 divisors, whose sum is σ = 3124973911134. Its totient is φ = 3124973911132.

The previous prime is 3124973911123. The next prime is 3124973911217. The reversal of 3124973911133 is 3311193794213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2978375285209 + 146598625924 = 1725797^2 + 382882^2 .

It is an emirp because it is prime and its reverse (3311193794213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3124973911133 - 218 = 3124973648989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3124973911123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562486955566 + 1562486955567.

It is an arithmetic number, because the mean of its divisors is an integer number (1562486955567).

Almost surely, 23124973911133 is an apocalyptic number.

It is an amenable number.

3124973911133 is a deficient number, since it is larger than the sum of its proper divisors (1).

3124973911133 is an equidigital number, since it uses as much as digits as its factorization.

3124973911133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 367416, while the sum is 47.

The spelling of 3124973911133 in words is "three trillion, one hundred twenty-four billion, nine hundred seventy-three million, nine hundred eleven thousand, one hundred thirty-three".