Base | Representation |
---|---|
bin | 101101011110100100110… |
… | …000100111011100000111 |
3 | 102001202200221101020022222 |
4 | 231132210300213130013 |
5 | 402200410042311241 |
6 | 10351411034242555 |
7 | 441534334604222 |
oct | 55364460473407 |
9 | 12052627336288 |
10 | 3125205432071 |
11 | aa5434aa0a78 |
12 | 425828b8645b |
13 | 1989232b2798 |
14 | ab3916d85b9 |
15 | 564616cea4b |
hex | 2d7a4c27707 |
3125205432071 has 2 divisors, whose sum is σ = 3125205432072. Its totient is φ = 3125205432070.
The previous prime is 3125205432017. The next prime is 3125205432131. The reversal of 3125205432071 is 1702345025213.
Together with previous prime (3125205432017) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3125205432071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3125205432971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562602716035 + 1562602716036.
It is an arithmetic number, because the mean of its divisors is an integer number (1562602716036).
Almost surely, 23125205432071 is an apocalyptic number.
3125205432071 is a deficient number, since it is larger than the sum of its proper divisors (1).
3125205432071 is an equidigital number, since it uses as much as digits as its factorization.
3125205432071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 35.
The spelling of 3125205432071 in words is "three trillion, one hundred twenty-five billion, two hundred five million, four hundred thirty-two thousand, seventy-one".
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