Base | Representation |
---|---|
bin | 1110001101100011111101… |
… | …11101101011000100011111 |
3 | 11002122200200100221000210102 |
4 | 13012301332331223010133 |
5 | 13044014213402021421 |
6 | 150245040342331315 |
7 | 6403622300100134 |
oct | 706617675530437 |
9 | 132580610830712 |
10 | 31252312142111 |
11 | 9a5a038504845 |
12 | 3608aa8129b3b |
13 | 14591078006a8 |
14 | 7a089731458b |
15 | 392e2732860b |
hex | 1c6c7ef6b11f |
31252312142111 has 2 divisors, whose sum is σ = 31252312142112. Its totient is φ = 31252312142110.
The previous prime is 31252312142089. The next prime is 31252312142167. The reversal of 31252312142111 is 11124121325213.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31252312142111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31252312142171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15626156071055 + 15626156071056.
It is an arithmetic number, because the mean of its divisors is an integer number (15626156071056).
Almost surely, 231252312142111 is an apocalyptic number.
31252312142111 is a deficient number, since it is larger than the sum of its proper divisors (1).
31252312142111 is an equidigital number, since it uses as much as digits as its factorization.
31252312142111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2880, while the sum is 29.
Adding to 31252312142111 its reverse (11124121325213), we get a palindrome (42376433467324).
The spelling of 31252312142111 in words is "thirty-one trillion, two hundred fifty-two billion, three hundred twelve million, one hundred forty-two thousand, one hundred eleven".
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