Base | Representation |
---|---|
bin | 1110001101100101010000… |
… | …11011110100110010101011 |
3 | 11002122202110212010210210112 |
4 | 13012302220123310302223 |
5 | 13044022130011141412 |
6 | 150245233355204535 |
7 | 6403645446043112 |
oct | 706625033646253 |
9 | 132582425123715 |
10 | 31253007912107 |
11 | 9a5a365225073 |
12 | 360906114674b |
13 | 14591b89bb607 |
14 | 7a09218aac79 |
15 | 392e68462722 |
hex | 1c6ca86f4cab |
31253007912107 has 2 divisors, whose sum is σ = 31253007912108. Its totient is φ = 31253007912106.
The previous prime is 31253007911999. The next prime is 31253007912109. The reversal of 31253007912107 is 70121970035213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31253007912107 - 242 = 26854961401003 is a prime.
Together with 31253007912109, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (31253007912109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15626503956053 + 15626503956054.
It is an arithmetic number, because the mean of its divisors is an integer number (15626503956054).
Almost surely, 231253007912107 is an apocalyptic number.
31253007912107 is a deficient number, since it is larger than the sum of its proper divisors (1).
31253007912107 is an equidigital number, since it uses as much as digits as its factorization.
31253007912107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 79380, while the sum is 41.
The spelling of 31253007912107 in words is "thirty-one trillion, two hundred fifty-three billion, seven million, nine hundred twelve thousand, one hundred seven".
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