Base | Representation |
---|---|
bin | 1110001101100101010010… |
… | …01100000000100001001011 |
3 | 11002122202111201220112012021 |
4 | 13012302221030000201023 |
5 | 13044022141224334201 |
6 | 150245234530025311 |
7 | 6403645661311036 |
oct | 706625114004113 |
9 | 132582451815167 |
10 | 31253020543051 |
11 | 9a5a37137196a |
12 | 3609065418237 |
13 | 14591bb4c1848 |
14 | 7a092343801d |
15 | 392e69609ea1 |
hex | 1c6ca930084b |
31253020543051 has 2 divisors, whose sum is σ = 31253020543052. Its totient is φ = 31253020543050.
The previous prime is 31253020543033. The next prime is 31253020543067. The reversal of 31253020543051 is 15034502035213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31253020543051 - 27 = 31253020542923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31253020542998 and 31253020543016.
It is not a weakly prime, because it can be changed into another prime (31253020543001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15626510271525 + 15626510271526.
It is an arithmetic number, because the mean of its divisors is an integer number (15626510271526).
Almost surely, 231253020543051 is an apocalyptic number.
31253020543051 is a deficient number, since it is larger than the sum of its proper divisors (1).
31253020543051 is an equidigital number, since it uses as much as digits as its factorization.
31253020543051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 31253020543051 its reverse (15034502035213), we get a palindrome (46287522578264).
The spelling of 31253020543051 in words is "thirty-one trillion, two hundred fifty-three billion, twenty million, five hundred forty-three thousand, fifty-one".
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