Search a number
-
+
3125313438857 is a prime number
BaseRepresentation
bin101101011110101011001…
…100101000010010001001
3102001202222110121112210022
4231132223030220102021
5402201120220020412
610351425453230225
7441540115624631
oct55365314502211
912052873545708
103125313438857
11aa548aa61085
12425859192375
1319893c79a81c
14ab3a1bb16c1
155646ae16a72
hex2d7ab328489

3125313438857 has 2 divisors, whose sum is σ = 3125313438858. Its totient is φ = 3125313438856.

The previous prime is 3125313438851. The next prime is 3125313438887. The reversal of 3125313438857 is 7588343135213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3124731471481 + 581967376 = 1767691^2 + 24124^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3125313438857 is a prime.

It is a super-2 number, since 2×31253134388572 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3125313438799 and 3125313438808.

It is not a weakly prime, because it can be changed into another prime (3125313438851) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562656719428 + 1562656719429.

It is an arithmetic number, because the mean of its divisors is an integer number (1562656719429).

Almost surely, 23125313438857 is an apocalyptic number.

It is an amenable number.

3125313438857 is a deficient number, since it is larger than the sum of its proper divisors (1).

3125313438857 is an equidigital number, since it uses as much as digits as its factorization.

3125313438857 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7257600, while the sum is 53.

The spelling of 3125313438857 in words is "three trillion, one hundred twenty-five billion, three hundred thirteen million, four hundred thirty-eight thousand, eight hundred fifty-seven".