Base | Representation |
---|---|
bin | 101101011110101100110… |
… | …011111110101100101001 |
3 | 102001210001100120222220102 |
4 | 231132230303332230221 |
5 | 402201144134001442 |
6 | 10351432302035145 |
7 | 441540565124132 |
oct | 55365463765451 |
9 | 12053040528812 |
10 | 3125340531497 |
11 | aa54a4286198 |
12 | 425866278ab5 |
13 | 198945295382 |
14 | ab3a5624c89 |
15 | 5646d4b9232 |
hex | 2d7accfeb29 |
3125340531497 has 2 divisors, whose sum is σ = 3125340531498. Its totient is φ = 3125340531496.
The previous prime is 3125340531449. The next prime is 3125340531527. The reversal of 3125340531497 is 7941350435213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3125314836736 + 25694761 = 1767856^2 + 5069^2 .
It is a cyclic number.
It is not a de Polignac number, because 3125340531497 - 214 = 3125340515113 is a prime.
It is a super-2 number, since 2×31253405314972 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3125340531427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562670265748 + 1562670265749.
It is an arithmetic number, because the mean of its divisors is an integer number (1562670265749).
Almost surely, 23125340531497 is an apocalyptic number.
It is an amenable number.
3125340531497 is a deficient number, since it is larger than the sum of its proper divisors (1).
3125340531497 is an equidigital number, since it uses as much as digits as its factorization.
3125340531497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1360800, while the sum is 47.
The spelling of 3125340531497 in words is "three trillion, one hundred twenty-five billion, three hundred forty million, five hundred thirty-one thousand, four hundred ninety-seven".
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