312540521341 has 2 divisors, whose sum is σ = 312540521342. Its totient is φ = 312540521340.

The previous prime is 312540521311. The next prime is 312540521347. The reversal of 312540521341 is 143125045213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 246061634116 + 66478887225 = 496046^2 + 257835^2 .

It is a cyclic number.

It is not a de Polignac number, because 312540521341 - 2⁵ = 312540521309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312540521347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156270260670 + 156270260671.

It is an arithmetic number, because the mean of its divisors is an integer number (156270260671).

Almost surely, 2^312540521341 is an apocalyptic number.

It is an amenable number.

312540521341 is a deficient number, since it is larger than the sum of its proper divisors (1).

312540521341 is an equidigital number, since it uses as much as digits as its factorization.

312540521341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 312540521341 its reverse (143125045213), we get a palindrome (455665566554).

The spelling of 312540521341 in words is "three hundred twelve billion, five hundred forty million, five hundred twenty-one thousand, three hundred forty-one".